Termination w.r.t. Q of the following Term Rewriting System could not be shown:

Q restricted rewrite system:
The TRS R consists of the following rules:

and3(not1(not1(x)), y, not1(z)) -> and3(y, band2(x, z), x)

Q is empty.


QTRS
  ↳ Non-Overlap Check

Q restricted rewrite system:
The TRS R consists of the following rules:

and3(not1(not1(x)), y, not1(z)) -> and3(y, band2(x, z), x)

Q is empty.

The TRS is non-overlapping. Hence, we can switch to innermost.

↳ QTRS
  ↳ Non-Overlap Check
QTRS
      ↳ DependencyPairsProof

Q restricted rewrite system:
The TRS R consists of the following rules:

and3(not1(not1(x)), y, not1(z)) -> and3(y, band2(x, z), x)

The set Q consists of the following terms:

and3(not1(not1(x0)), x1, not1(x2))


Q DP problem:
The TRS P consists of the following rules:

AND3(not1(not1(x)), y, not1(z)) -> AND3(y, band2(x, z), x)

The TRS R consists of the following rules:

and3(not1(not1(x)), y, not1(z)) -> and3(y, band2(x, z), x)

The set Q consists of the following terms:

and3(not1(not1(x0)), x1, not1(x2))

We have to consider all minimal (P,Q,R)-chains.

↳ QTRS
  ↳ Non-Overlap Check
    ↳ QTRS
      ↳ DependencyPairsProof
QDP

Q DP problem:
The TRS P consists of the following rules:

AND3(not1(not1(x)), y, not1(z)) -> AND3(y, band2(x, z), x)

The TRS R consists of the following rules:

and3(not1(not1(x)), y, not1(z)) -> and3(y, band2(x, z), x)

The set Q consists of the following terms:

and3(not1(not1(x0)), x1, not1(x2))

We have to consider all minimal (P,Q,R)-chains.